0.005x^2=-0.3x+18

Solution for 0.005x^2=-0.3x+18 equation:

0.005x^2=-0.3x+18

We move all terms to the left:

0.005x^2-(-0.3x+18)=0

We get rid of parentheses

0.005x^2+0.3x-18=0

a = 0.005; b = 0.3; c = -18;
Δ = b2-4ac
Δ = 0.32-4·0.005·(-18)
Δ = 0.45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.3)-\sqrt{0.45}}{2*0.005}=\frac{-0.3-\sqrt{0.45}}{0.01}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.3)+\sqrt{0.45}}{2*0.005}=\frac{-0.3+\sqrt{0.45}}{0.01}
$